8x^2-8x=-x^2-2x-1

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Solution for 8x^2-8x=-x^2-2x-1 equation: 



8x^2-8x=-x^2-2x-1

We move all terms to the left:

8x^2-8x-(-x^2-2x-1)=0

We get rid of parentheses

8x^2+x^2+2x-8x+1=0

We add all the numbers together, and all the variables

9x^2-6x+1=0

a = 9; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·9·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{6}{18}=1/3$

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